How much does an aluminum pipe that is 16 ft long, 4 ft in diameter, and 3/4 inch thick weigh?

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To determine the weight of the aluminum pipe, it is essential to understand how to calculate the volume of the material used in the pipe and then multiply that volume by the density of aluminum.

First, the outer diameter of the pipe is 4 feet, which can be converted to inches for consistency in calculations (4 ft = 48 inches). The thickness of the pipe is 3/4 inch, which means the inner diameter can be calculated as follows:

Inner diameter = Outer diameter - 2 * Thickness = 48 inches - 2 * (3/4 inch) = 48 inches - 1.5 inches = 46.5 inches.

Next, we can calculate the volume of aluminum in the pipe. The formula for the volume of a cylinder is:

Volume = π * (radius)² * height.

The outer radius is 24 inches (48 inches / 2) and the inner radius is 23.25 inches (46.5 inches / 2). The height (length) of the pipe is 16 feet, which is 192 inches (since 1 ft = 12 inches). The volume of the aluminum is then calculated as the difference between the outer volume and the inner volume:

Volume

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