What is the approximate weight of a cylindrical steel tank that is 10 ft high with a diameter of 6 ft and 3/4 inch thick walls?

To determine the approximate weight of the cylindrical steel tank, we first need to calculate its volume and then multiply that by the density of steel to find the weight.

1. Calculate the volume of the steel material: We need to find the volume of the entire cylinder without the hollow section (i.e., the outer volume) and then subtract the volume of the hollow interior (i.e., the inner volume).

• Outer radius: The diameter is 6 ft, so the outer radius is 3 ft.
• Inner radius: Since the walls are 3/4 inch thick, we convert that to feet (3/4 inch = 0.0625 ft). Therefore, the inner radius is 3 ft - 0.0625 ft = 2.9375 ft.
• Height: The height of the tank is 10 ft.

2. Volume calculations:
   • Outer volume (V_outer) = π × (outer radius)² × height = π × (3 ft)² × 10 ft = π × 9 ft² × 10 ft = 90π ft³.
   • Inner volume (V_inner) = π ×