What is the approximate weight of a cylindrical aluminum tank that is 16 ft high with a diameter of 7 ft and walls that are 3/4 inch thick?

To determine the weight of a cylindrical aluminum tank with specific dimensions, we first need to calculate the tank's volume and then find its weight based on the density of aluminum.

1. Calculate the volume of the aluminum used for the tank: The tank consists of a cylinder with a certain wall thickness. First, we calculate the outer volume of the cylinder using the outer dimensions and then subtract the inner volume calculated from the inner dimensions.

• Outer radius: The diameter is 7 feet, so the outer radius is 3.5 feet. The wall thickness is 3/4 inch, which converts to feet as follows: 3/4 inch = 0.0625 feet. Therefore, the inner radius will be 3.5 feet - 0.0625 feet = 3.4375 feet.
• Height: 16 feet.

Outer volume ( V_{outer} ): [ V_{outer} = \pi \times (3.5)^2 \times 16 ]

Inner volume ( V_{inner} ): [ V_{inner} = \pi \times (3.4375